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\begin{align*}A\land B &= B\land A & \text{commutativity}\\&= X & \text{as defined above}\end{align*}
Is this how syntactically this is done? If not, how is it done?
Thanks in advance.
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\begin{align*}A\land B &= B\land A & \text{commutativity}\\&= X & \text{as defined above}\end{align*}
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\begin{align*}a &= 1 & b &= 2 \\c &= 3 & d &= 4\end{align*}
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\begin{align*}A\land B &= B\land A && \text{commutativity}\\&= X && \text{as defined above}\end{align*}
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\begin{align}\text{minimize}\quad&\sum_{ij}c_{ij}x_{ij}\label{obj}\\\text{subject to}\quad&\sum_{j}x_{ij} \geq 1\stepcounter{equation}\label{everything}\tag*{$\forall i\quad$(\theequation)}\end{align}References are wrong, though, as in \ref{everything}.
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\begin{align}\text{minimize}\quad & \sum_{i\in I}\sum_{j\in (P\cap \mathcal{A})} x_{ij}y_j-\sum_i\sum_j k_iy_j+N\cdot\sum_ik_i\\\text{subject to}\quad & \sum_i x_{ij} = 1 \hspace{5cm}\forall j\in (P\cap \mathcal{A}) | j \geq \zeta\label{alloneX}\end{align}
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