Graphics, Figures & Tables ⇒ Drawing interlocking tori using sketch/tikz

[moitetajni]

Hello.

I am trying to create the graph of some interlocking tori like these two

interlocking_tori2.png (39.63 KiB) Viewed 3804 times

Since I am not an expert on tikz or sketch, I have been modifying some code I found on the web. So here's the code I have been running so far:

Code: Select all

def torus {
    def n_segs 60
    sweep [draw=none, fill=cyan, fill opacity=0.75] {n_segs, rotate(360/n_segs, (0,0,0), [0,1,0])}
        sweep {n_segs, rotate(360/n_segs, (1.5,0,0), [0,0,1])}
        (2,0,0)
}

def torus2 {
	def n_segs 60
	sweep [draw=none, fill=orange, fill opacity=0.75] {n_segs, rotate(360/n_segs, (1.5,0,0), [0,0,1]) }
		sweep {n_segs, rotate(360/n_segs, (0,0,0), [0,1,0])}
		(2,0,0)

}

put { view((10,4,2)) } {{torus2} {torus}}

global { language tikz }

Here, torus2 was the code I created based on torus. However it is not doing the trick, since I I get is this mess:

failed_interlocking_tori.png (87.02 KiB) Viewed 3804 times

So my question would be: how can I redefine torus2 so the whole image looks like the one I want?

[Stefan Kottwitz]

Welcome to the forum!

So what did you use - Sketch?

I could imagine making it using pgfplots, which bases on TikZ. Such as this example from TeXwelt, by Henri and Ross:

Code: Select all

\documentclass[margin=2mm,tikz]{standalone}
\usepackage{pgfplots}
\begin{document}
%Oberflächenproblem
\begin{tikzpicture}[line width=.7pt]
\begin{axis}[axis equal image,
    clip=false,
    xlabel=\empty, ylabel=\empty, zlabel=\empty,
    axis lines=middle,
    colormap/blackwhite,
    %y dir=reverse,
    %axis on top
    ]
    % sym. Torus:
            \addplot3[domain=0:360,y domain=0:360, samples=50,
            surf,z buffer=sort
            ]
            ({15+(10+4*cos(x))*cos(y)} ,
            {15+(10+4*cos(x))*sin(y)},
            {4+4*sin(x)});
\end{axis}
\end{tikzpicture} 
\end{document}

torus.png (60.05 KiB) Viewed 3797 times

Two tori may be split in parts and drawn in an order so the back would be behind the front.

Stefan