Graphics, Figures & Tables ⇒ Take formula to the left (not centered)

[MakezHD]

I have a formula (using cases) centered and I want to take it to the left, but I don't know how to do it. Could someone help me? Thanks.

[Johannes_B]

Please post a minimal working example as text (code), not an image. Please follow the link for instructions.

[Stefan Kottwitz]

Hi,

please take a look at your last question and the answer: function by parts help. Johannes already said, please copy & paste your code here, don't show an image. If a reader wants to help and test and improve your code, he has to type everything what he sees in your image! Post text (code), so it can be copied, and even used in the online compiler.

Stefan

[MakezHD]

Code: Select all

 \\
1)\[ f(x,y) =
\begin{cases}
xy\dfrac{x^2-y^2}{x^2+y^2} & \left(x,y\right) \neq \left(0,0\right)\\
0 & \left(x,y\right) = \left(0,0\right)
\end{cases}
\; , \; D_{12}f(0,0) \neq D_{21}f(0,0).
\]
\\

There you go

[Stefan Kottwitz]

• For flushed left equations, add the class option fleqn.
  For left equation numbers, add the class option leqno.
• Use an equation environment instead of \[ ... \] if you would like to have numbers.
• The \\ before and after the formula are not good, they cause errors.

Complete sample:

Code: Select all

\documentclass[fleqn,leqno]{article}
\usepackage{amsmath}
\setlength{\mathindent}{0pt}
\begin{document}
\begin{equation}
  f(x,y) =
    \begin{cases}
      xy\dfrac{x^2-y^2}{x^2+y^2} & \left(x,y\right) \neq \left(0,0\right)\\
      0 & \left(x,y\right) = \left(0,0\right)
    \end{cases}
  \; , \; D_{12}f(0,0) \neq D_{21}f(0,0).
\end{equation}
\end{document}

Also for questions it would be good to take a minute more and to post a compilable minimal working example, as I did with the solution here. So with preamble.

Stefan