General ⇒ Many Errors Compiling Latex

[cabellicar123]

Hi. I am pretty new to LaTeX. I am getting errors compiling this code, but I cannot figure out why it is generating so many errors: http://pastebin.com/gcU8MxPv. The following is produced:

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**electrolysis_of_water_and_aqueous_solutions.tex
(./electrolysis_of_water_and_aqueous_solutions.tex
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! LaTeX Error: Bad math environment delimiter.

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Type  H <return>  for immediate help.
 ...                                              
                                                  
l.86 ...reduction): & \(2H_{2}O_{(l)} + 2e^{-}\) &
                                                  
? 
! Missing $ inserted.
<inserted text> 
                $
l.86 ...reduction): & \(2H_{2}O_{(l)} + 2e^{-}\) &
                                                  
? 

! LaTeX Error: Bad math environment delimiter.

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Type  H <return>  for immediate help.
 ...                                              
                                                  
l.88     Anode (oxidation): & \(2I^{-}_{(aq)}\) &
                                                  \(I_{2(s)} + 2e^{-}\)\\
? 
! Missing $ inserted.
<inserted text> 
                $
l.88     Anode (oxidation): & \(2I^{-}_{(aq)}\) &
                                                  \(I_{2(s)} + 2e^{-}\)\\
? 

! LaTeX Error: Bad math environment delimiter.

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Type  H <return>  for immediate help.
 ...                                              
                                                  
l.91 ...reduction): & \(2H_{2}O_{(l)} + 2e^{-}\) &
                                                  
? 
! Missing $ inserted.
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                $
l.91 ...reduction): & \(2H_{2}O_{(l)} + 2e^{-}\) &
                                                  
? 

! LaTeX Error: Bad math environment delimiter.

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Type  H <return>  for immediate help.
 ...                                              
                                                  
l.93     Anode (oxidation): & \(2Br^{-}_{(aq)}\) &
                                                   \(Br_{2(l)} + 2e^{-}\)\\
? 
! Missing $ inserted.
<inserted text> 
                $
l.93     Anode (oxidation): & \(2Br^{-}_{(aq)}\) &
                                                   \(Br_{2(l)} + 2e^{-}\)\\
? 

! LaTeX Error: Bad math environment delimiter.

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Type  H <return>  for immediate help.
 ...                                              
                                                  
l.96 ...reduction): & \(2H_{2}O_{(l)} + 2e^{-}\) &
                                                  
? 
! Missing $ inserted.
<inserted text> 
                $
l.96 ...reduction): & \(2H_{2}O_{(l)} + 2e^{-}\) &
                                                  
? 

! LaTeX Error: Bad math environment delimiter.

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Type  H <return>  for immediate help.
 ...                                              
                                                  
l.98     Anode (oxidation): & \(2Cl^{-}_{(aq)}\) &
                                                   \(Cl_{2(g)} + 2e^{-}\)\\
? 
! Missing $ inserted.
<inserted text> 
                $
l.98     Anode (oxidation): & \(2Cl^{-}_{(aq)}\) &
                                                   \(Cl_{2(g)} + 2e^{-}\)\\
? 

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! LaTeX Error: Bad math environment delimiter.

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Type  H <return>  for immediate help.
 ...                                              
                                                  
l.111 ...lution: & \(KI_{(aq)} + 2H_{2}O_{(l)}\) &
                                                   \(KOH_{(aq)} + 2H_{2(g)} +
? 
! Missing $ inserted.
<inserted text> 
                $
l.111 ...lution: & \(KI_{(aq)} + 2H_{2}O_{(l)}\) &
                                                   \(KOH_{(aq)} + 2H_{2(g)} +
? 

! LaTeX Error: Bad math environment delimiter.

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 ...                                              
                                                  
l.113 ...ution: & \(KBr_{(aq)} + 2H_{2}O_{(l)}\) &
                                                   \(KOH_{(aq)} + 2H_{2(g)} +
? 
! Missing $ inserted.
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                $
l.113 ...ution: & \(KBr_{(aq)} + 2H_{2}O_{(l)}\) &
                                                   \(KOH_{(aq)} + 2H_{2(g)} +
? 

! LaTeX Error: Bad math environment delimiter.

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 ...                                              
                                                  
l.115 ...ution: & \(KCl_{(aq)} + 2H_{2}O_{(l)}\) &
                                                   \(KOH_{(aq)} + 2H_{2(g)} +
? 
! Missing $ inserted.
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                $
l.115 ...ution: & \(KCl_{(aq)} + 2H_{2}O_{(l)}\) &
                                                   \(KOH_{(aq)} + 2H_{2(g)} +
? 

! LaTeX Error: Bad math environment delimiter.

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 ...                                              
                                                  
l.122 ... (reduction): & \(K^{+}_{(l)} + e^{-}\) &
                                                   \(K_{(s)}\)\\
? 
! Missing $ inserted.
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                $
l.122 ... (reduction): & \(K^{+}_{(l)} + e^{-}\) &
                                                   \(K_{(s)}\)\\
? 

! LaTeX Error: Bad math environment delimiter.

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 ...                                              
                                                  
l.123     Anode (oxidation): & \(2I^{-}_{(l)}\) &
                                                  \(I_{2(s)} + 2e^{-}\)\\
? 
! Missing $ inserted.
<inserted text> 
                $
l.123     Anode (oxidation): & \(2I^{-}_{(l)}\) &
                                                  \(I_{2(s)} + 2e^{-}\)\\
? 

! LaTeX Error: Bad math environment delimiter.

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Type  H <return>  for immediate help.
 ...                                              
                                                  
l.124     Overall Equation: & \(2KI_{(l)}\) &
                                              \(2K_{(s)} + I_{2(s)}\)\\
? 
! Missing $ inserted.
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                $
l.124     Overall Equation: & \(2KI_{(l)}\) &
                                              \(2K_{(s)} + I_{2(s)}\)\\
? 

! LaTeX Error: Bad math environment delimiter.

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 ...                                              
                                                  
l.129 ... (reduction): & \(K^{+}_{(l)} + e^{-}\) &
                                                   \(K_{(s)}\)\\
? 
! Missing $ inserted.
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                $
l.129 ... (reduction): & \(K^{+}_{(l)} + e^{-}\) &
                                                   \(K_{(s)}\)\\
? 

! LaTeX Error: Bad math environment delimiter.

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Type  H <return>  for immediate help.
 ...                                              
                                                  
l.130     Anode (oxidation): & \(2Br^{-}_{(l)}\) &
                                                   \(Br_{2(l)} + 2e^{-}\)\\
? 
! Missing $ inserted.
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                $
l.130     Anode (oxidation): & \(2Br^{-}_{(l)}\) &
                                                   \(Br_{2(l)} + 2e^{-}\)\\
? 

! LaTeX Error: Bad math environment delimiter.

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Type  H <return>  for immediate help.
 ...                                              
                                                  
l.131     Overall Equation: & \(2KBr_{(l)}\) &
                                               \(2K_{(s)} + Br_{2(s)}\)\\
? 
! Missing $ inserted.
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                $
l.131     Overall Equation: & \(2KBr_{(l)}\) &
                                               \(2K_{(s)} + Br_{2(s)}\)\\
? 

! LaTeX Error: Bad math environment delimiter.

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 ...                                              
                                                  
l.136 ... (reduction): & \(K^{+}_{(l)} + e^{-}\) &
                                                   \(K_{(s)}\)\\
? 
! Missing $ inserted.
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                $
l.136 ... (reduction): & \(K^{+}_{(l)} + e^{-}\) &
                                                   \(K_{(s)}\)\\
? 

! LaTeX Error: Bad math environment delimiter.

See the LaTeX manual or LaTeX Companion for explanation.
Type  H <return>  for immediate help.
 ...                                              
                                                  
l.137     Anode (oxidation): & \(2Cl^{-}_{(l)}\) &
                                                   \(Cl_{2(g)} + 2e^{-}\)\\
? 
! Missing $ inserted.
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                $
l.137     Anode (oxidation): & \(2Cl^{-}_{(l)}\) &
                                                   \(Cl_{2(g)} + 2e^{-}\)\\
? 

! LaTeX Error: Bad math environment delimiter.

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Type  H <return>  for immediate help.
 ...                                              
                                                  
l.138     Overall Equation: & \(2KCl_{(l)}\) &
                                               \(2K_{(s)} + Cl_{2(g)}\)\\
? 
! Missing $ inserted.
<inserted text> 
                $
l.138     Overall Equation: & \(2KCl_{(l)}\) &
                                               \(2K_{(s)} + Cl_{2(g)}\)\\
? 

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[3] (./electrolysis_of_water_and_aqueous_solutions.aux) ) 
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[Stefan Kottwitz]

Welcome to the forum!

You can add also code to the forum post. There's a button for it. The same like you did with the .log file. One of the benefits is, that we can easily open it by one click in the online LaTeX compiler. Here is the code from the paste bin:

Code: Select all

\documentclass[12pt]{article}
\title{Electrolysis of Water and Aqueous Solutions}
\author{Carlo Abelli \\ AP Chemistry --- Mr.\ Kern}
\date{February 19, 2015}

\usepackage[margin=1.0in]{geometry}

\begin{document}
  \begin{titlepage}
    \maketitle
    \thispagestyle{empty}
  \end{titlepage}
  \section{Water Electrolysis Calculations and Questions}
  \subsection{Half Reaction for Each Electrode}
  Cathode (reduction): \(2H^{+}_{(aq)} + 2e^{-} \rightarrow H_{2(g)}\)\\
  This reaction took place at the cathode because during the splint test the gas
  produced a popping sound, characteristic of hydrogen, a highly flammable gas.
  \\
  \\
  Anode (oxidation): \(2H_{2}O_{(l)} \rightarrow O_{2(g)} + 4H^{+}_{(aq)} +
   4e^{-}\)\\
  This reaction took place at the anode because during the splint test the gas
  reignited the splint ember, characteristic of oxygen.
  \subsection{Overall Reaction}
  \(2H_{2}O_{(l)} \rightarrow 2H_{2(g)} + O_{2(g)}\)
  \subsection{Average Current}
  Average Current: \(\frac{0.44 + 0.43 + 0.44 + 0.44 + 0.45 + 0.46 + 0.45 + 0.46
    + 0.46 + 0.45 + 0.45 + 0.46 + 0.45 + 0.47 + 0.46}{15} = 0.45\)
  \subsection{Amount of Hydrogen Produced in One Hour}
  \(\frac{0.45\ coulombs}{1.00\ \sec} * \frac{60.0\ \sec}{1.00\ \min} *
    \frac{60.0\ \min}{1.00\ hour} * \frac{1.00\ e^{-}}{1.60*10^{-19}\ coulombs} *
    \frac{1.00\ mol\ e^{-}}{6.022*10^{23}\ e^{-}} * \frac{1.00\ mol\ H_{2}}
    {2.00\ mol\ e^{-}} = 0.0084\ mol\ H_{2}\)\\
  \(0.0084\ mol\ H_{2} * 22.4\ L/mol = 0.19\ L\ H_{2}\)\\
  \(0.0084\ mol\ H_{2} * 2.016\ g/mol = 0.0017\ g\ H_{2}\)
  \subsection{Amount of Time Needed to Produce 30 mL Oxygen Gas at
  22\(^{\circ}\)C and 1.00 atm}
  \(1.00\ atm * 0.030\ L = n * 0.08206\ L\ atm\ K^{-1}\ mol^{-1} * 295\ K\)\\
  \(n = 0.0012\ mol\ O_{2}\)\\
  \(0.0012\ mol\ O_{2} * \frac{4.00\ mol\ e^{-}}{1.00\ mol\ O_{2}} *
    \frac{6.022*10^{23}\ e^{-}}{1.00\ mol\ e^{-}} *
    \frac{1.60*10^{-19}\ coulombs}{1\ e^{-}} * \frac{1.00\ \sec}{0.45\ coulombs}
    = 100.\ \sec\)
  \subsection{Moles of Gas Produced in Experiment}
  Cathode (Hydrogen)\\
  \(P_{container} = 36.8\ cm\ H_{2}O * \frac{10.0\ mm}{1.00\ cm} *
    \frac{1.08\ g\ H_{2}O} {1\ mL\ H_{2}O} * \frac{1\ mL\ Hg}
    {13.534\ g\ Hg} + 751.1\ mm\ Hg = 780.5\ mm\ Hg\)\\
  \(P_{gas} = P_{container} - P_{H_{2}O}\)\\
  \(P_{gas} = 780.5\ mm\ Hg - 18.7\ mm\ Hg = 761.8\ mm\ Hg\)\\
  \(761.8\ mm\ Hg * 0.0486\ L = n * 62.363\ L\ mmHg\ K^{-1}\ mol^{-1} * 294.0\ K\)
  \\
  \(n = 0.00202\ mol\ H_{2}\)\\
  \\
  Anode (Oxygen)\\
  \(P_{container} = 24.0\ cm\ H_{2}O * \frac{10.0\ mm}{1.00\ cm} *
    \frac{1.08\ g\ H_{2}O} {1\ mL\ H_{2}O} * \frac{1\ mL\ Hg}
    {13.534\ g\ Hg} + 751.1\ mm\ Hg = 770.3\ mm\ Hg\)\\
  \(P_{gas} = P_{container} - P_{H_{2}O}\)\\
  \(P_{gas} = 770.3\ mm\ Hg - 18.7\ mm\ Hg = 751.6\ mm\ Hg\)\\
  \(751.6\ mm\ Hg * 0.0239\ L = n * 62.363\ L\ mmHg\ K^{-1}\ mol^{-1} * 294.0\ K\)
  \\
  \(n = 0.000980\ mol\ O_{2}\)
  \subsection{Theoretical Moles of Gas Produced}
  Cathode (Hydrogen)\\
  \(\frac{0.45\ coulombs}{1.00\ \sec} * \frac{60.0\ \sec}{1.00\ \min} * 14.0\ \min *
    \frac{1.00\ e^{-}}{1.60*10^{-19}\ coulombs} * \frac{1.00\ mol\ e^{-}}
    {6.022*10^{23}\ e^{-}} * \frac{1.00\ mol\ H_{2}}{2.00\ mol\ e^{-}} =
    0.0020\ mol\ H_{2}\)\\
  \\
  Anode (Oxygen)\\
  \(\frac{0.45\ coulombs}{1.00\ \sec} * \frac{60.0\ \sec}{1.00\ \min} * 14.0\ \min *
    \frac{1.00\ e^{-}}{1.60*10^{-19}\ coulombs} * \frac{1.00\ mol\ e^{-}}
    {6.022*10^{23}\ e^{-}} * \frac{1.00\ mol\ O_{2}}{4.00\ mol\ e^{-}} =
    0.00098\ mol\ O_{2}\)
  \subsection{Percent Deviation}
  Cathode (Hydrogen)\\
  \(\frac{0.00202\ mol - 0.0020\ mol}{0.0020\ mol} * 100 = 0.0\%\ deviation\)\\
  \\
  Anode (Oxygen)\\
  \(\frac{0.000980\ mol - 0.00098\ mol}{0.00098\ mol} * 100 = 0.0\%\ deviation\)
  \section{Aqueous KI, KBr and KCl Electrolysis Calculations and Questions}
  \subsection{Half Reactions for Each Electrode}
  \begin{tabular}{ l r @{\(\rightarrow\)} l }
    KI Solution\\
    Cathode (reduction): & \(2H_{2}O_{(l)} + 2e^{-}\) &
      \(2OH^{-}_{(aq)} + H_{2(g)}\)\\
    Anode (oxidation): & \(2I^{-}_{(aq)}\) & \(I_{2(s)} + 2e^{-}\)\\
    \\
    KBr Solution\\
    Cathode (reduction): & \(2H_{2}O_{(l)} + 2e^{-}\) &
      \(2OH^{-}_{(aq)} + H_{2(g)}\)\\
    Anode (oxidation): & \(2Br^{-}_{(aq)}\) & \(Br_{2(l)} + 2e^{-}\)\\
    \\
    KCl Solution\\
    Cathode (reduction): & \(2H_{2}O_{(l)} + 2e^{-}\) &
      \(2OH^{-}_{(aq)} + H_{2(g)}\)\\
    Anode (oxidation): & \(2Cl^{-}_{(aq)}\) & \(Cl_{2(g)} + 2e^{-}\)\\
  \end{tabular}\\
  \\
  The water half reaction had to have occurred at the cathode because the
  phenolphthalein indicator was activated by the creation of \(OH^{-}\),
  creating the purple color observed at the cathode.\\
  \\
  The iodine, chlorine and bromine half reactions had to have occurred at the
  anode because in the first experiment, a dark solid was created at the anode
  (iodine), in the second experiment, a yellow liquid was observed (bromine)
  and in the third experiment, a chlorine smelling gas was produced (chlorine).
  \subsection{Overall Equations}
  \begin{tabular}{ l r @{\(\rightarrow\)} l }
    KI Solution: & \(KI_{(aq)} + 2H_{2}O_{(l)}\) & \(KOH_{(aq)} + 2H_{2(g)} +
      I_{2(s)}\)\\
    KBr Solution: & \(KBr_{(aq)} + 2H_{2}O_{(l)}\) & \(KOH_{(aq)} + 2H_{2(g)} +
      Br_{2(l)}\)\\
    KCl Solution: & \(KCl_{(aq)} + 2H_{2}O_{(l)}\) & \(KOH_{(aq)} + 2H_{2(g)} +
      Cl_{2(g)}\)\\
    Test Solution:
  \end{tabular}
  \subsection{Half Reactions and Overall Equation for Molten KI, KBr and KCl}
  KI\\
  \begin{tabular}{ l r @{\(\rightarrow\)} l }
    Cathode (reduction): & \(K^{+}_{(l)} + e^{-}\) & \(K_{(s)}\)\\
    Anode (oxidation): & \(2I^{-}_{(l)}\) & \(I_{2(s)} + 2e^{-}\)\\
    Overall Equation: & \(2KI_{(l)}\) & \(2K_{(s)} + I_{2(s)}\)\\
  \end{tabular}\\
  \\
  KBr\\
  \begin{tabular}{ l r @{\(\rightarrow\)} l }
    Cathode (reduction): & \(K^{+}_{(l)} + e^{-}\) & \(K_{(s)}\)\\
    Anode (oxidation): & \(2Br^{-}_{(l)}\) & \(Br_{2(l)} + 2e^{-}\)\\
    Overall Equation: & \(2KBr_{(l)}\) & \(2K_{(s)} + Br_{2(s)}\)\\
  \end{tabular}\\
  \\
  KCl\\
  \begin{tabular}{ l r @{\(\rightarrow\)} l }
    Cathode (reduction): & \(K^{+}_{(l)} + e^{-}\) & \(K_{(s)}\)\\
    Anode (oxidation): & \(2Cl^{-}_{(l)}\) & \(Cl_{2(g)} + 2e^{-}\)\\
    Overall Equation: & \(2KCl_{(l)}\) & \(2K_{(s)} + Cl_{2(g)}\)\\
  \end{tabular}
  \subsection{Time Required to Produce 1.25 g Iodine at 0.75 amps}
  \(1.25\ g\ I_{2} * \frac{1.00\ mol\ I_{2}}{253.80\ g} *
    \frac{2.00\ mol\ e^{-}}{1.00\ mol\ I_{2}} *
    \frac{6.022*10^{23}\ e^{-}}{1.00\ mol\ e^{-}} *
    \frac{1.60*10^{-19}\ coulombs}{1.00\ e^{-}} *
    \frac{1.00\ \sec}{0.75\ coulombs} *
    \frac{1.00\ \min}{60.0\ \sec} = 21\ \min\)
  \subsection{Time Required to Produce 0.100 L Hydrogen gas in Lab Conditions at
    0.75 amps}
  \(751.1\ mmHg * 0.100\ L\ H_{2} = n * 62.363\ L\ mmHg\ K^{-1}\ mol^{-1} *
  294\ K\)\\
  \(n = 0.00410\ mol\)\\
  \(0.00410\ mol\ H_{2} * \frac{2.00\ mol\ e^{-}}{1.00\ mol\ H_{2}} *
    \frac{6.022*10^{23}\ e^{-}}{1.00\ mol\ e^{-}} *
    \frac{1.60*10^{-19}\ coulombs}{1.00\ e^{-}} *
    \frac{1.00\ \sec}{0.75\ coulombs} * \frac{1.00\ \min}{60.0\ \sec} = 18\ \min\)
\end{document}

I will have a look at it now.

Stefan

[Stefan Kottwitz]

Now I reduced your code to a minimal working example, which produces the same error like the first one in the original code:

Code: Select all

\documentclass[12pt]{article}
\begin{document}
  \begin{tabular}{ l r @{\(\rightarrow\)} l }
    KI Solution\\
    Cathode (reduction): & $2H_{2}O_{(l)} + 2e^{-}$ &
      \(2OH^{-}_{(aq)} + H_{2(g)}\)
  \end{tabular}
\end{document}

It brings:

Code: Select all

! LaTeX Error: Bad math environment delimiter.

See the LaTeX manual or LaTeX Companion for explanation.
Type  H <return>  for immediate help.
 ...                                              
                                                  
l.7 ...e (reduction): & $2H_{2}O_{(l)} + 2e^{-}$ &

The root cause of the problem is the \(\rightarrow\) in the tabular column head, since \( ... \) is not robust. In the newest LaTeX version, this is fixed. With an older LaTeX version, this can be fixed by adding to the preamble:

Code: Select all

\usepackage{fixltx2e}

Alternatively it's fixed by $\rightarrow$.

However, the appearance of the chemical equations is pretty wrong regarding spacing and custom style, such as using upright letters for atoms. I will make some code to show it in the next post.

Stefan

[Stefan Kottwitz]

Here is my recommendation for writing chemical equations. I would use chemmacros or chemformula.

Code: Select all

\documentclass{article}
\usepackage{chemformula}
\begin{document}
  Cathode (reduction):
  \ch{2 H2O_{(l)} + 2 e- -> 2 OH_{(aq)}- + H2_{(g)}}
\end{document}

For my next book, I made a demonstration example for writing chemical formulas. It shows how you can simply write chemical formulas and equations with an easy syntax, even easier than math, with different examples, such as with subscripts for numbers of atoms, isotopes with left subscripts, reaction arrows, bonds, and electric charges of ions. It works in math and text mode and even respects the outer font, such as bold and sans-serif in the heading.

Code: Select all

\documentclass{scrartcl}
\usepackage{chemformula}
\pagestyle{empty}
\begin{document}
\section*{About \ch{Na2SO4}}
\ch{Na2SO4} is sodium sulfate.
It contains \ch{Na+} and \ch{SO4^2-}.
\ch{Na2SO4 * 10 H2O} is a decahydrate.
\[
\ch{Na2SO4 + 2 C -> Na2S + 2 CO2}
\]
\begin{equation}
\ch{Na2SO4 + H2SO4 <=> 2 NaHSO4}
\end{equation}
\section*{Isotopes}
\ch{^{232}_{92}U140} is uranium-232.
\section*{Hydrocarbons}
\begin{itemize}
  \item \ch{H3C-CH3} is ethane,
  \item \ch{H2C=CH2} is ethylene,
  \item \ch{H2C+CH2} is ethyne.
\end{itemize}
\end{document}

chemical-formula.png (27.14 KiB) Viewed 6147 times

Stefan

[Johannes_B]

Please note, that you should not have \maketitle in the {titlepage} environment. If you want a titlepage, use titlepage as option to the documentclass.

[cgnieder]

Apart from chemformula which also would be my choice (but I'm biased) I also seriously recommend using siunitx for typesetting numbers and units and also recommend reading mathmode. For example you might want to use \cdot instead of * for denoting a product operation.

One small example. You have

Code: Select all

\subsection{Amount of Hydrogen Produced in One Hour}
  \(\frac{0.45\ coulombs}{1.00\ \sec} * \frac{60.0\ \sec}{1.00\ \min} *
    \frac{60.0\ \min}{1.00\ hour} * \frac{1.00\ e^{-}}{1.60*10^{-19}\ coulombs} *
    \frac{1.00\ mol\ e^{-}}{6.022*10^{23}\ e^{-}} * \frac{1.00\ mol\ H_{2}}
    {2.00\ mol\ e^{-}} = 0.0084\ mol\ H_{2}\)\\
  \(0.0084\ mol\ H_{2} * 22.4\ L/mol = 0.19\ L\ H_{2}\)\\
  \(0.0084\ mol\ H_{2} * 2.016\ g/mol = 0.0017\ g\ H_{2}\)

In your document. I'd rather do something like

Code: Select all

\begin{align*}
  &\frac{\SI{0.45}{\coulomb}}{\SI{1.00}{\second}} \cdot
  \frac{\SI{60.0}{\second}}{\SI{1.00}{\minute}} \cdot
  \frac{\SI{60.0}{\minute}}{\SI{1.00}{\hour}} \cdot
  \frac{1.00\,\el}{\SI{1.60e-19}{\coulomb}} \cdot
  \frac{\SI{1.00}{\mole}\,\el}{\num{6.022e23}\,\el} \cdot
  \frac{\SI{1.00}{\mole}\,\ch{H2}}{\SI{2.00}{\mole}\,\el} \\
  &= \SI{0.0084}{\mole}\, \ch{H2}
\end{align*}

This uses amsmath, chemmacros and siunitx. A complete example with a direct comparison:

Code: Select all

\documentclass{article}

\usepackage{chemmacros}
\chemsetup{phases/pos=sub}

\usepackage{siunitx}
\sisetup{exponent-product=\cdot}

\usepackage{mathtools}

\begin{document}
\subsection{Amount of Hydrogen Produced in One Hour}
  \(\frac{0.45\ coulombs}{1.00\ \sec} * \frac{60.0\ \sec}{1.00\ \min} *
    \frac{60.0\ \min}{1.00\ hour} * \frac{1.00\ e^{-}}{1.60*10^{-19}\ coulombs} *
    \frac{1.00\ mol\ e^{-}}{6.022*10^{23}\ e^{-}} * \frac{1.00\ mol\ H_{2}}
    {2.00\ mol\ e^{-}} = 0.0084\ mol\ H_{2}\)\\
  \(0.0084\ mol\ H_{2} * 22.4\ L/mol = 0.19\ L\ H_{2}\)\\
  \(0.0084\ mol\ H_{2} * 2.016\ g/mol = 0.0017\ g\ H_{2}\)

\subsection{My suggestion}
\begin{align*}
  &\frac{\SI{0.45}{\coulomb}}{\SI{1.00}{\second}} \cdot
  \frac{\SI{60.0}{\second}}{\SI{1.00}{\minute}} \cdot
  \frac{\SI{60.0}{\minute}}{\SI{1.00}{\hour}} \cdot
  \frac{1.00\,\el}{\SI{1.60e-19}{\coulomb}} \cdot
  \frac{\SI{1.00}{\mole}\,\el}{\num{6.022e23}\,\el} \cdot
  \frac{\SI{1.00}{\mole}\,\ch{H2}}{\SI{2.00}{\mole}\,\el} \\
  &= \SI{0.0084}{\mole}\, \ch{H2}
\end{align*}

\end{document}

Best regards

[Stefan Kottwitz]

Very nice, here's an image of Clemens' solution for easy comparing for the quick reader.

units.png (32.3 KiB) Viewed 6132 times

Stefan