Graphics, Figures & Tables ⇒ PSTricks | 2D Analogue for drawCoor?

[svend_tveskaeg]

Hi all.

Is there an option similar to drawCoor from the pst-3dplot package for 2D plots.

What I would like to do is to highlight the coordinates for a point i R^2 by drawing a dotted (or dashed) line from the point and perpendicular onto each axes. This is of course not difficult to do manually, but an option to do it automatic would be nice.

Thank you in advance!

[CrazyHorse]

Is there an option similar to drawCoor from the pst-3dplot package for 2D plots.

What I would like to do is to highlight the coordinates for a point i R^2 by drawing a dotted (or dashed) line from the point and perpendicular onto each axes. This is of course not difficult to do manually, but an option to do it automatic would be nice.

it is simple to write an own macro \psDots(#1,#2) which draws the coordinates.
A _little bit_ more complicated is an optional argument. Have a look at pstricks.tex how \psTextFrame is defined.

[svend_tveskaeg]

Thank you, Herbert.

I have only two such points in the entire document so I will not define my own macro for this.

[svend_tveskaeg]

I now see that I actually have some more points so here is a possible solution.

Code: Select all

\documentclass{article}

\usepackage{auto-pst-pdf,pstricks-add}

\newcommand{\intersection}[2]{%
  \psline[linestyle=dotted](0,#2)(#1,#2)(#1,0)
  \psdot(#1,#2)
}

\begin{document}

\begin{figure}
 \centering
  \begin{pspicture}(-1.5,-0.5)(5.8,11)
   \psset{algebraic}
    \psaxes{->}(0,0)(-1.5,-0.5)(5.5,10.5)[$x$,0][$y$,90]
    \psplot[linewidth=1.25pt,linecolor=blue]{-1.2}{5.2}{x^2-4*x+4}
    \rput(4.15,6){$p$}
    \psplot[linewidth=1.25pt,linecolor=red]{-1.2}{5.5}{x+4}
    \rput(2,6.5){$m$}
    \intersection{5}{9}
  \end{pspicture}
\end{figure}

\end{document}

[svend_tveskaeg]

I have assumed that the \psaxes intersect at (0,0).

@Herbert (or others): If I would like to

(1) have the \psaxes intersectinon at some other point than (0,0), and
(2) give some options to the line color and dot color

how do I do modity \intersection to accomplish that?

I do not quite understand how to do this after I had a look at pstricks.tex. It is probably a rather simple task but I cannot figure it out.

[CrazyHorse]

I have assumed that the \psaxes intersect at (0,0).

@Herbert (or others): If I would like to

(1) have the \psaxes intersectinon at some other point than (0,0), and
(2) give some options to the line color and dot color

how do I do modity \intersection to accomplish that?

I do not quite understand how to do this after I had a look at pstricks.tex. It is probably a rather simple task but I cannot figure it out.

Code: Select all

\documentclass{article}
\usepackage{pstricks-add}

\makeatletter
\def\psDot{\pst@object{psDot}}
\def\psDot@i(#1){{%
    \addbefore@par{linestyle=dotted}
    \use@par
    \psline({0,0}|#1)(#1)(#1|{0,0}) % (x,y | x,y) x from 1st, y from 2nd
    \psdot(#1)
}}
\makeatother

\begin{document}

\begin{figure}
 \centering
  \begin{pspicture}(-1.5,-0.5)(5.8,11)
   \psset{algebraic}
    \psaxes{->}(0,0)(-1.5,-0.5)(5.5,10.5)[$x$,0][$y$,90]
    \psplot[linewidth=1.25pt,linecolor=blue]{-1.2}{5.2}{x^2-4*x+4}
    \rput(4.15,6){$p$}
    \psplot[linewidth=1.25pt,linecolor=red]{-1.2}{5.5}{x+4}
    \rput(2,6.5){$m$}
    \psDot(5,9)
    \psDot[linestyle=dashed,linecolor=blue](4,4)
  \end{pspicture}
\end{figure}

\end{document}

[svend_tveskaeg]

Perfect!

[svend_tveskaeg]

I have just found section 14.1 of the pst-plot manual.