Graphics, Figures & Tables ⇒ chemfig | Distance Bond—Molecule

[svend_tveskaeg]

Hi all.

Consider the following MWE:

Code: Select all

\documentclass{article}
\usepackage{chemfig}

\begin{document}

\setbondoffset{4pt}
\chemfig{CH_3-\lewis{0:2:,O}(-[6]H)-[:-0,,,,dash pattern=on 1.8pt off 1.8pt]H}

\end{document}

How do I get a larger distance between the electrons at the oxygen atom and the (dashed) bound connecting oxygen and hydrogen?

I know that \setbondoffset does the trick but I cannot figure out what to put it in my \chemfig argument in order to make it work.

Thank you in advance!

P.S. I have looked at page 12 of the English chemfig manual.

[unbonpetit]

You can use "#"

Code: Select all

\chemfig{CH_3-\lewis{0:2:,O}(-[6]H)-#(5pt)[:-0,,,,dash pattern=on 1.8pt off 1.8pt]H}

[svend_tveskaeg]

Thank you. In the MWE it works just fine but for some (to me unknown) reason, the following code will not compile.

Code: Select all

\documentclass[danish]{beamer}
\usepackage{babel}
\usepackage{chemfig}

\begin{document}

\begin{frame}{Alcohol}
\begin{center}
\setbondoffset{4pt}
\chemfig{CH_3-\lewis{0:2:,O}(-[6]H)-#(5pt)[:-0,,,,dash pattern=on 1.8pt off 1.8pt]H-\lewis{0:2:,O}(-[6]CH_3)-#(5pt)[:-0,,,,dash pattern=on 1.8pt off 1.8pt]H-\lewis{0:2:,O}(-[6]CH_3)}
\end{center}
\end{frame}

\end{document}

What is wrong here?

Notice that I use the beamer class here.

Thank you in advance!

P.S. The log file is attached.

[unbonpetit]

Try

Code: Select all

{\catcode`\#=12
\begin{frame}{Alcohol}
\begin{center}
\setbondoffset{4pt}
\chemfig{CH_3-\lewis{0:2:,O}(-[6]H)-#(5pt)[:-0,,,,dash pattern=on 1.8pt off 1.8pt]H-\lewis{0:2:,O}(-[6]CH_3)-#(5pt)[:-0,,,,dash pattern=on 1.8pt off 1.8pt]H-\lewis{0:2:,O}(-[6]CH_3)}
\end{center}
\end{frame}}

[svend_tveskaeg]

I love it! Thank you very much!