General ⇒ probsoln | Problems without Solutions

[rafapa]

I'm trying to use Nicola Talbot's probsoln package. I have problems with solutions included but I also have problems without solution. I am using

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\hideanswers
\loadallproblems[tema01]{tema1.tex}
\begin{enumerate}
\foreachproblem[tema01]{\item\label{\thisproblemlabel}\thisproblem}
end{enumerate}
\section*{Soluciones}
\showanswers
\begin{enumerate}
\foreachproblem[tema01]{\item\thisproblem}
\end{enumerate}
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
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Following the FAQ of probsoln I define problems without solutions with:

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\begin{defproblem}{inheritance}%
Describe what is meant by the term \emph{inheritance} in
object-oriented programming. Use examples.%
\end{defproblem}
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
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and problems with solutions with:

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\begin{defproblem}{t01:02}%
\begin{onlyproblem}%
 Velocidad de una molecula%
\end{onlyproblem}%
\begin{onlysolution}%
0.0791.
\end{onlysolution}%
\end{defproblem}
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
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The problem with this setup is that in the solution part the enunciate of the problem is displayed. I would like something like:

Problems:

1. text 1
2. text 2
3. text 3
4. text 4

Solutions:

1. solution 1
2. solution 2
4. solution 4

Where the problem number three has no solution.
I mean, if the solution is empty no number should be printed. I have tried defining:

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\begin{defproblem}{inheritance}%
\begin{onlyproblem}%
Describe what is meant by the term \emph{inheritance} in
object-oriented programming. Use examples.%
\end{onlyproblem}%
\begin{onlysolution}%
\end{onlysolution}%
\end{defproblem}
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
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In this way I get

Solutions:

1. solution 1
2. solution 2
3.
4. solution 4

Is there a way to avoid the display of the item with no solution?

Thanks in advance for the attention

[nlct]

The new version (3.01) now has a command called \foreachsolution that works like \foreachproblem but only iterates through problems that contain the onlysolution environment.

Regards
Nicola Talbot

[rafapa]

Thanks a lot for the new foreachsolution command.

It almost works.

Please try the following modified sample7.tex

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\documentclass{article}
\usepackage{tikz}
\usepackage{probsoln}
\usepackage{paralist}
\loadallproblems{prob-mixed}
\begin{document}
\section{Exercises}
\begin{enumerate}[\bfseries 1.]
  \foreachproblem{\item\label{q-\thisproblemlabel} \thisproblem}
\end{enumerate}
\section{Solutions}
\showanswers
\begin{enumerate}[\bfseries 1.]
  \foreachsolution{\item[\ref{q-\thisproblemlabel}] \thisproblem}
\end{enumerate}
\end{document}
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
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I have added the package paralist in order to use the [\bfseries 1.] option to the enumerate environment. The problem is that the foreachproblem part use the option but the foreachsolution does not.
If I change to

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\begin{enumerate}
  \foreachsolution{\item[{\bfseries \ref{q-\thisproblemlabel}.}] \thisproblem}
\end{enumerate}
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
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Run LaTeX here

It seems to work ok.

Anyway I thank you again.

[nlct]

In \foreachsolution you've used the optional argument of \item which overrides the format set at the start of the environment. An alternative is to set the counter before \item so that you don't need the optional argument. You can use the refcount package:

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\documentclass{article}
\usepackage{tikz}
\usepackage{probsoln}
\usepackage{paralist}
\usepackage{refcount}
\loadallproblems{prob-mixed}
\makeatletter
\newcommand{\setproblemcounter}{%
  \setcounterref{\@enumctr}{q-\thisproblemlabel}%
  \addtocounter{\@enumctr}{-1}%
}
\makeatother
\begin{document}
\section{Exercises}
\begin{enumerate}[\bfseries 1.]
\foreachproblem{\item\label{q-\thisproblemlabel} \thisproblem}
\end{enumerate}
\section{Solutions}
\showanswers
\begin{enumerate}[\bfseries 1.]
\foreachsolution{\setproblemcounter \item \thisproblem}
\end{enumerate}
\end{document}
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
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Run LaTeX here

Regards
Nicola Talbot

[rafapa]

First,
a big thank you.

My version of refcount is:

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Package: refcount 2010/12/01 v3.2 Data extraction from references (HO)
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
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After compiling your example the following error appears:

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! Undefined control sequence.
\rc@set ...safe@activestrue\endcsname \rc@refused 
                                                  {#4}\expandafter \rc@@set ...
l.27 ...ion{\setproblemcounter \item \thisproblem}
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
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Searching in comp.text.tex I have found a workaround suggested by refcount's author.

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\makeatletter
\let\rc@refused\refused
\makatother
 
 
הההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההההה
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Run LaTeX here

Thanks again.


Rafael