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\begin{table}[htbp]\begin{center}\begin{tabular}{>{$\displaystyle}p{.2\textwidth}<{$} >{$\displaystyle}p{.3\textwidth}<{$}}%================================%\toprule\textbf{Derivative} & \textbf{Expression} \\\toprule\dfrac{\partial \mathbi{X}\transp\mathbf{A}\mathbi{X}}{\partial\mathbi{X}} &= \underbrace{\left(\mathbf{A}+\mathbf{A}\transp\right)\mathbi{X}}_{\textit{Column Vector}} &\\\dfrac{\partial \mathbi{X}\transp\mathbf{A}\mathbi{X}}{\partial\mathbi{X}\transp} &= \underbrace{\mathbi{X}\transp\left(\mathbf{A}+\mathbf{A}\transp\right)}_{\textit{Row Vector}}&\\%================================%\midrule\dfrac{\partial \mathbi{A}\transp\mathbi{X}}{\partial \mathbi{X}} &= \mathbi{A} \\\dfrac{\partial \mathbi{X}\transp\mathbi{A}}{\partial\mathbi{X}} &= \mathbi{A}\\\dfrac{\partial \mathbi{A}\transp\mathbi{X}}{\partial \mathbi{X}\transp} &= \mathbi{A}\transp \\\dfrac{\partial \mathbi{X}\transp\mathbi{A}}{\partial\mathbi{X}\transp} &= \mathbi{A}\transp \\%================================%%\midrule%\dfrac{\partial}{\partial} &= \\%\dfrac{\partial}{\partial} &=%================================%\bottomrule\end{tabular}\end{center}\end{table}
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\renewcommand{\arraystretch}{1.1}
Any clues how to solve this?
Thanks