Information and discussion about graphics, figures & tables in LaTeX documents.
maddus
Posts: 3 Joined: Sat Jun 11, 2011 6:45 pm
Post
by maddus » Sat Jun 11, 2011 6:49 pm
I try to put the Text "Arithmetisches Mittel" more down to the line. Here is a small sample...
Code: Select all
\documentclass{article}
\usepackage{booktabs}
\usepackage{array}
\usepackage{ragged2e}
\usepackage{multirow}
\begin{document}
\renewcommand\multirowsetup{\RaggedRight}
\newcolumntype{N}{>{}} \newcolumntype{C}{>{}c}
\newcolumntype{N}{>{}} \newcolumntype{L}{>{}l}
\newcolumntype{N}{>{}} \newcolumntype{R}{>{}r}
\newcommand\mc[3]{\multicolumn{#1}{#2}{#3}}
\begin{table}[!h]
\begin{center}
\begin{tabular}{@{} *{6}{r} @{}} \toprule
& \multirow{2}{7em}{%
Arithmetisches Mittel} & & & \mc{2}{C}{Quartile} \\ \cmidrule(l){5-6}
\mc{1}{L}{VW Passat} & & \mc{1}{R}{Median} & \mc{1}{R}{Modus} & \mc{1}{R}{25} & \mc{1}{R}{75} \\ \cmidrule(r){1-1} \cmidrule(lr){2-2} \cmidrule(lr){3-3} \cmidrule(lr){4-4} \cmidrule(lr){5-5} \cmidrule(l){6-6}
\mc{1}{L}{Preis} & 12\,585,39 & 13\,000 & 16\,000 & 5\,100 & 17\,745 \\
\mc{1}{L}{Laufleistung} & 110\,661,27 & 113\,000 & 150\,000 & 67\,195 & 150\,500 \\
\bottomrule
\end{tabular}
\end{center}
\end{table}
\end{document}
thx
maddus
Last edited by
maddus on Sat Jun 11, 2011 7:36 pm, edited 1 time in total.
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Stefan Kottwitz
Site Admin
Posts: 10348 Joined: Mon Mar 10, 2008 9:44 pm
Post
by Stefan Kottwitz » Sat Jun 11, 2011 6:59 pm
H maddus,
you can use \multirow in the next line, with a negative row number:
Code: Select all
\begin{tabular}{@{} *{6}{r} @{}} \toprule
& & & & \mc{2}{C}{Quartile} \\ \cmidrule(l){5-6}
\mc{1}{L}{VW Passat} & \multirow{-2}{7em}{%
Arithmetisches Mittel} & \mc{1}{R}{Median} & \mc{1}{R}{Modus} & \mc{1}{R}{25} & \mc{1}{R}{75} \\ \cmidrule(r){1-1} \cmidrule(lr){2-2} \cmidrule(lr){3-3} \cmidrule(lr){4-4} \cmidrule(lr){5-5} \cmidrule(l){6-6}
Stefan
LaTeX.org admin
maddus
Posts: 3 Joined: Sat Jun 11, 2011 6:45 pm
Post
by maddus » Sat Jun 11, 2011 7:08 pm
Thank you very much. That was the solution. Here again the correct result. I down't know if to ask in this thread or open a new one. Is it possible to arrange "Arithmetisches Mittel" to right instead of left like now?
Code: Select all
\documentclass{article}
\usepackage{booktabs}
\usepackage{array}
\usepackage{ragged2e}
\usepackage{multirow}
\begin{document}
\renewcommand\multirowsetup{\RaggedRight}
\newcolumntype{N}{>{}} \newcolumntype{C}{>{}c}
\newcolumntype{N}{>{}} \newcolumntype{L}{>{}l}
\newcolumntype{N}{>{}} \newcolumntype{R}{>{}r}
\newcommand\mc[3]{\multicolumn{#1}{#2}{#3}}
\begin{table}[!h]
\begin{center}
\begin{tabular}{@{} *{6}{r} @{}} \toprule
& & & & \mc{2}{C}{Quartile} \\ \cmidrule(l){5-6}
\mc{1}{L}{VW Passat} &\multirow{-2}{7em}{%
Arithmetisches Mittel} & \mc{1}{R}{Median} & \mc{1}{R}{Modus} & \mc{1}{R}{25} & \mc{1}{R}{75} \\ \cmidrule(r){1-1} \cmidrule(lr){2-2} \cmidrule(lr){3-3} \cmidrule(lr){4-4} \cmidrule(lr){5-5} \cmidrule(l){6-6}
\mc{1}{L}{Preis} & 12\,585,39 & 13\,000 & 16\,000 & 5\,100 & 17\,745 \\
\mc{1}{L}{Laufleistung} & 110\,661,27 & 113\,000 & 150\,000 & 67\,195 & 150\,500 \\
\bottomrule
\end{tabular}
\end{center}
\end{table}
\end{document}
thx
maddus
Stefan Kottwitz
Site Admin
Posts: 10348 Joined: Mon Mar 10, 2008 9:44 pm
Post
by Stefan Kottwitz » Sat Jun 11, 2011 7:19 pm
No problem, just insert \raggedleft in the \multirow cell.
Code: Select all
\multirow{-2}{\raggedleft Arithmetisches Mittel}
Stefan
LaTeX.org admin
maddus
Posts: 3 Joined: Sat Jun 11, 2011 6:45 pm
Post
by maddus » Sat Jun 11, 2011 7:23 pm
Thanks a lot. Here the full solution...
Code: Select all
\documentclass{article}
\usepackage{booktabs}
\usepackage{array}
\usepackage{ragged2e}
\usepackage{multirow}
\begin{document}
\renewcommand\multirowsetup{\RaggedRight}
\newcolumntype{N}{>{}} \newcolumntype{C}{>{}c}
\newcolumntype{N}{>{}} \newcolumntype{L}{>{}l}
\newcolumntype{N}{>{}} \newcolumntype{R}{>{}r}
\newcommand\mc[3]{\multicolumn{#1}{#2}{#3}}
\begin{table}[!h]
\begin{center}
\begin{tabular}{@{} *{6}{r}} \toprule
& & & & \mc{2}{C}{Quartile} \\ \cmidrule(l){5-6}
\mc{1}{L}{VW Passat} &\multirow{-2}{7em}{%
\raggedleft Arithmetisches Mittel} & \mc{1}{R}{Median} & \mc{1}{R}{Modus} & \mc{1}{R}{25} & \mc{1}{R}{75} \\ \cmidrule(r){1-1} \cmidrule(lr){2-2} \cmidrule(lr){3-3} \cmidrule(lr){4-4} \cmidrule(lr){5-5} \cmidrule(l){6-6}
\mc{1}{L}{Preis} & 12\,585,39 & 13\,000 & 16\,000 & 5\,100 & 17\,745 \\
\mc{1}{L}{Laufleistung} & 110\,661,27 & 113\,000 & 150\,000 & 67\,195 & 150\,500 \\
\bottomrule
\end{tabular}
\end{center}
\end{table}
\end{document}