Math & Science ⇒ Proper aligning of equations
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Proper aligning of equations
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Re: Proper aligning of equations
[1] http://latex-community.org/forum/viewto ... =46&t=7878
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- Joined: Tue Mar 25, 2008 5:02 pm
Re: Proper aligning of equations
If you want them numbered as you show, please provide the source. If we can't see what you did, we can't see what you did wrong.

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Proper aligning of equations
Note*: I have updated more equations but the problem remains the same. Please put the new additional code into texnicenter to see yourself. Thanks!
Code: Select all
\documentclass{report}
\usepackage[makeroom,fleqn,margin=1in]{amsmath,fullpage,cancel,multicol,geometry}
\pagestyle{empty}
\providecommand{\e}[1]{\ensuremath{\times 10^{#1}}}
\begin{document}
\begin{enumerate}
\item
$\begin{aligned}[t]
s&=r\theta \\
\frac{s}{r}&=\theta \\
\frac{8.29\e{6}}{6.18\e{6}}&=\theta \\
\text{1.34 rad}&=\theta \\
\end{aligned}$
\item
$\begin{aligned}[t]
\Delta t &=\text{9.09 \cancel{hr}}\left(\frac{\text{60 \cancel{min}}}{\text{1 \cancel{hr}}}\right)\left(\frac{\text{60 s}}{\text{1 \cancel{min}}}\right)=\text{32,724 s} \\
\omega &= ? \\
\omega&=\frac{\theta}{\Delta t}=\frac{\text{1.34 rad}}{\text{32,724 s}}=\text{4.09\e{-5} rad/s}}
\end{aligned}$
\item
$\begin{aligned}[t]
\[
v_{1}&=\frac{2\pi r}{T} & v_{2}&=\frac{2\pi(r+d)}{T} \\
Tv_{1}&=2\pi r & Tv_{2}&=2\pi(r+d) \\
\frac{Tv_{1}}{2\pi}&=r & \frac{Tv_{2}}{2\pi}-d&=r \\
\frac{Tv_{1}}{2\pi}&=\frac{Tv_{2}}{2\pi}-d \\
d&=\frac{Tv_{2}}{2\pi}-\frac{Tv_{1}}{2\pi} \\
d&=\frac{T}{2\pi}\left(v_{2}-v_{1}\right) \\
\frac{2\pi d}{T}&=\Delta v \\
\frac{2\pi(328)}{86,400}&=\Delta v \\
0.02385&=\Delta v \\
\text{2.39\e{-2} m/s}&=\Delta v
\]
\end{aligned}$
\item
$\begin{aligned}[t]
v&=\frac{2\pi d}{T} \\
v&=\frac{2\pi r\cos\theta}{T} \\
v&=\frac{2\pi(6.37\e{6})\cos40.1}{\text{86,400 s}} \\
v&=\text{354.34 m/s} \\
\end{aligned}$
\item
$\begin{aligned}[t]
T_{2}\cos\theta_{2}&=T_{1}\cos\theta_{1} \\
T_{2}&=\frac{T_{1}\cos\theta_{1}}{\cos\theta_{2}} \\
T_{1}\sin\theta_{1}+\left(\frac{T_{1}\cos\theta_{1}}{\cos\theta_{2}}\right)\sin\theta_{2}&=350 \\
T_{1}\sin\theta_{1}+\frac{T_{1}\cos\theta_{1}\sin\theta_{2}}{\cos\theta_{2}}&=350 \\
T_{1}\sin\theta_{1}+T_{1}\frac{\cos\theta_{1}\sin\theta_{2}}{\cos\theta_{2}}&=350 \\
T_{1}\left(\sin\theta_{1}+\frac{\cos\theta_{1}\sin\theta_{2}}{\cos\theta_{2}}\right)&=350 \\
T_{1}\left(\frac{\sin\theta_{1}\cos\theta_{2}+\cos\theta_{1}\sin\theta_{2}}{\cos\theta_{2}}\right)&=350 \\
T_{1}\left(\frac{\sin\left(\theta_{1}+\theta_{2}\right)}{\cos\theta_{2}}\right)&=350 \\
T_{1}&=350\left(\frac{\cos\theta_{2}}{\sin\left(\theta_{1}+\theta_{2}\right)}\right) \\
T_{1}&=\frac{350\cos\theta_{2}}{\sin\left(\theta_{1}+\theta_{2}\right)} \\
T_{1}&=\frac{350\cos23.8}{\sin\left(55.3+23.8\right)} \\
T_{1}&=\frac{350\cos23.8}{\sin\left(79.1\right)} \\
T_{1}&=\text{326.12 N}
\end{aligned}$
\item
$\begin{aligned}[t]
T_{1}\sin\theta_{1}&=350-T_{2}\sin\theta_{2} \\
T_{1}&=\frac{350-T_{2}\sin\theta_{2}}{\sin\theta_{1}} \\
-\left(\frac{350-T_{2}\sin\theta_{2}}{\sin\theta_{1}}\right)\cos\theta_{1}+T_{2}\cos\theta_{2}&=0 \\
-\left(\frac{350\cos\theta_{1}-T_{2}\sin\theta_{2}\cos\theta_{1}}{\sin\theta_{1}}\right)+T_{2}\cos\theta_{2}&=0 \\
\frac{-350\cos\theta_{1}+T_{2}\sin\theta_{2}\cos\theta_{1}}{\sin\theta_{1}}+T_{2}\cos\theta_{2}&=0 \\
\frac{-350\cos\theta_{1}}{\sin\theta_{1}}+\frac{T_{2}\sin\theta_{2}\cos\theta_{1}}{\sin\theta_{1}}+T_{2}\cos\theta_{2}&=0 \\
\frac{-350\cos\theta_{1}}{\sin\theta_{1}}+T_{2}\left(\frac{\sin\theta_{2}\cos\theta_{1}}{\sin\theta_{1}}+\cos\theta_{2}\right)&=0 \\
T_{2}\left(\frac{\sin\theta_{2}\cos\theta_{1}}{\sin\theta_{1}}+\cos\theta_{2}\right)&=\frac{350\cos\theta_{1}}{\sin\theta_{1}} \\
T_{2}\left(\frac{\sin\theta_{2}\cos\theta_{1}+\cos\theta_{2}\sin\theta_{1}}{\sin\theta_{1}}\right)&=\frac{350\cos\theta_{1}}{\sin\theta_{1}} \\
T_{2}\left(\frac{\sin\left(\theta_{2}+\theta_{1}\right)}{\sin\theta_{1}}\right)&=\frac{350\cos\theta_{1}}{\sin\theta_{1}} \\
T_{2}&=\frac{350\cos\theta_{1}}{\sin\theta_{1}}\left(\frac{\sin\theta_{1}}{\sin\left(\theta_{2}+\theta_{1}\right)}\right) \\
T_{2}&=\frac{350\cos\theta_{1}}{\sin\left(\theta_{2}+\theta_{1}\right)} \\
T_{2}&=\frac{350\cos55.3}{\sin\left(23.8+55.3\right)} \\
T_{2}&=\text{203 N}
\end{aligned}$
\end{enumerate}
\end{document}
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- Posts: 707
- Joined: Tue Mar 25, 2008 5:02 pm
Proper aligning of equations
LaTeX Error: Unknown option `makeroom' for package `amsmath'
This happens because you use options to a specific package but include about six packages in the \usepackage command; try something like this:
Code: Select all
\documentclass{report}
\usepackage[margin=1in]{geometry}
\usepackage[fleqn]{amsmath}
\usepackage[makeroom]{cancel}
\usepackage{fullpage,multicol}
etc.
Code: Select all
\begin{align}
T_{2}\cos\theta_{2}&=T_{1}\cos\theta_{1} \\
T_{2}&=\frac{T_{1}\cos\theta_{1}}{\cos\theta_{2}} \\
T_{1}\sin\theta_{1}+\left(\frac{T_{1}\cos\theta_{1}}{\cos\theta_{2}}\right)\sin\theta_{2}&=350 \\
T_{1}\sin\theta_{1}+\frac{T_{1}\cos\theta_{1}\sin\theta_{2}}{\cos\theta_{2}}&=350 \\
T_{1}\sin\theta_{1}+T_{1}\frac{\cos\theta_{1}\sin\theta_{2}}{\cos\theta_{2}}&=350 \\
T_{1}\left(\sin\theta_{1}+\frac{\cos\theta_{1}\sin\theta_{2}}{\cos\theta_{2}}\right)&=350 \\
T_{1}\left(\frac{\sin\theta_{1}\cos\theta_{2}+\cos\theta_{1}\sin\theta_{2}}{\cos\theta_{2}}\right)&=350 \\
T_{1}\left(\frac{\sin\left(\theta_{1}+\theta_{2}\right)}{\cos\theta_{2}}\right)&=350 \\
T_{1}&=350\left(\frac{\cos\theta_{2}}{\sin\left(\theta_{1}+\theta_{2}\right)}\right) \\
T_{1}&=\frac{350\cos\theta_{2}}{\sin\left(\theta_{1}+\theta_{2}\right)} \\
T_{1}&=\frac{350\cos23.8}{\sin\left(55.3+23.8\right)} \\
T_{1}&=\frac{350\cos23.8}{\sin\left(79.1\right)} \\
T_{1}&=\text{326.12 N}
\end{align}
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- Posts: 402
- Joined: Fri May 20, 2011 9:41 am
Proper aligning of equations
Code: Select all
\documentclass{report}
\usepackage{fullpage,multicol}
\usepackage[margin=1in]{geometry}
\usepackage[fleqn]{amsmath}
\usepackage[makeroom]{cancel}
\pagestyle{empty}
\providecommand{\e}[1]{\ensuremath{\times 10^{#1}}}
\begin{document}
\begin{enumerate}
\item
$\begin{aligned}[t]
s&=r\theta \\
\frac{s}{r}&=\theta \\
\frac{8.29\e{6}}{6.18\e{6}}&=\theta \\
\text{1.34 rad}&=\theta \\
\end{aligned}$
\item
$\begin{aligned}[t]
\Delta t &=\text{9.09 \cancel{hr}}\left(\frac{\text{60 \cancel{min}}}{\text{1 \cancel{hr}}}\right)\left(\frac{\text{60 s}}{\text{1 \cancel{min}}}\right)=\text{32,724 s} \\
\omega &= ? \\
\omega&=\frac{\theta}{\Delta t}=\frac{\text{1.34 rad}}{\text{32,724 s}}=\text{4.09\e{-5} rad/s}
\end{aligned}$
\item
$\begin{aligned}[t]
v_{1}&=\frac{2\pi r}{T} & v_{2}&=\frac{2\pi(r+d)}{T} \\
Tv_{1}&=2\pi r & Tv_{2}&=2\pi(r+d) \\
\frac{Tv_{1}}{2\pi}&=r & \frac{Tv_{2}}{2\pi}-d&=r \\
\frac{Tv_{1}}{2\pi}&=\frac{Tv_{2}}{2\pi}-d \\
d&=\frac{Tv_{2}}{2\pi}-\frac{Tv_{1}}{2\pi} \\
d&=\frac{T}{2\pi}\left(v_{2}-v_{1}\right) \\
\frac{2\pi d}{T}&=\Delta v \\
\frac{2\pi(328)}{86,400}&=\Delta v \\
0.02385&=\Delta v \\
\text{2.39\e{-2} m/s}&=\Delta v
\end{aligned}$
\item
$\begin{aligned}[t]
v&=\frac{2\pi d}{T} \\
v&=\frac{2\pi r\cos\theta}{T} \\
v&=\frac{2\pi(6.37\e{6})\cos40.1}{\text{86,400 s}} \\
v&=\text{354.34 m/s} \\
\end{aligned}$
\item
$\begin{aligned}[t]
T_{2}\cos\theta_{2}&=T_{1}\cos\theta_{1} \\
T_{2}&=\frac{T_{1}\cos\theta_{1}}{\cos\theta_{2}} \\
T_{1}\sin\theta_{1}+\left(\frac{T_{1}\cos\theta_{1}}{\cos\theta_{2}}\right)\sin\theta_{2}&=350 \\
T_{1}\sin\theta_{1}+\frac{T_{1}\cos\theta_{1}\sin\theta_{2}}{\cos\theta_{2}}&=350 \\
T_{1}\sin\theta_{1}+T_{1}\frac{\cos\theta_{1}\sin\theta_{2}}{\cos\theta_{2}}&=350 \\
T_{1}\left(\sin\theta_{1}+\frac{\cos\theta_{1}\sin\theta_{2}}{\cos\theta_{2}}\right)&=350 \\
T_{1}\left(\frac{\sin\theta_{1}\cos\theta_{2}+\cos\theta_{1}\sin\theta_{2}}{\cos\theta_{2}}\right)&=350 \\
T_{1}\left(\frac{\sin\left(\theta_{1}+\theta_{2}\right)}{\cos\theta_{2}}\right)&=350 \\
T_{1}&=350\left(\frac{\cos\theta_{2}}{\sin\left(\theta_{1}+\theta_{2}\right)}\right) \\
T_{1}&=\frac{350\cos\theta_{2}}{\sin\left(\theta_{1}+\theta_{2}\right)} \\
T_{1}&=\frac{350\cos23.8}{\sin\left(55.3+23.8\right)} \\
T_{1}&=\frac{350\cos23.8}{\sin\left(79.1\right)} \\
T_{1}&=\text{326.12 N}
\end{aligned}$
\item
$\begin{aligned}[t]
T_{1}\sin\theta_{1}&=350-T_{2}\sin\theta_{2} \\
T_{1}&=\frac{350-T_{2}\sin\theta_{2}}{\sin\theta_{1}} \\
-\left(\frac{350-T_{2}\sin\theta_{2}}{\sin\theta_{1}}\right)\cos\theta_{1}+T_{2}\cos\theta_{2}&=0 \\
-\left(\frac{350\cos\theta_{1}-T_{2}\sin\theta_{2}\cos\theta_{1}}{\sin\theta_{1}}\right)+T_{2}\cos\theta_{2}&=0 \\
\frac{-350\cos\theta_{1}+T_{2}\sin\theta_{2}\cos\theta_{1}}{\sin\theta_{1}}+T_{2}\cos\theta_{2}&=0 \\
\frac{-350\cos\theta_{1}}{\sin\theta_{1}}+\frac{T_{2}\sin\theta_{2}\cos\theta_{1}}{\sin\theta_{1}}+T_{2}\cos\theta_{2}&=0 \\
\frac{-350\cos\theta_{1}}{\sin\theta_{1}}+T_{2}\left(\frac{\sin\theta_{2}\cos\theta_{1}}{\sin\theta_{1}}+\cos\theta_{2}\right)&=0 \\
T_{2}\left(\frac{\sin\theta_{2}\cos\theta_{1}}{\sin\theta_{1}}+\cos\theta_{2}\right)&=\frac{350\cos\theta_{1}}{\sin\theta_{1}} \\
T_{2}\left(\frac{\sin\theta_{2}\cos\theta_{1}+\cos\theta_{2}\sin\theta_{1}}{\sin\theta_{1}}\right)&=\frac{350\cos\theta_{1}}{\sin\theta_{1}} \\
T_{2}\left(\frac{\sin\left(\theta_{2}+\theta_{1}\right)}{\sin\theta_{1}}\right)&=\frac{350\cos\theta_{1}}{\sin\theta_{1}} \\
T_{2}&=\frac{350\cos\theta_{1}}{\sin\theta_{1}}\left(\frac{\sin\theta_{1}}{\sin\left(\theta_{2}+\theta_{1}\right)}\right) \\
T_{2}&=\frac{350\cos\theta_{1}}{\sin\left(\theta_{2}+\theta_{1}\right)} \\
T_{2}&=\frac{350\cos55.3}{\sin\left(23.8+55.3\right)} \\
T_{2}&=\text{203 N}
\end{aligned}$
\end{enumerate}
\end{document}
Also, when I try putting \begin{align*}...\end{align*} in enumerate environment wierd things happen and everything is screwed up! That's what I am trying to do all this time... is to number the first line of a "block of equations" and align them to the left as much as possible( and that does not mean to have them intended; i mean FULLY left-aligned plus all the equal signs MUST line up!).
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Re: Proper aligning of equations
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- Joined: Fri May 20, 2011 9:41 am
Re: Proper aligning of equations
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- Posts: 162
- Joined: Wed Jun 17, 2009 10:18 pm
Proper aligning of equations
Edit: Sorry if I'm being a little slow on the uptake here.
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- example.pdf
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Re: Proper aligning of equations
What i'm looking for is to have "1." "2." and corresponding "4." "5." to be aligned like "3." and im trying to do that but it's just not happening so help me with that.
P.S i don't know why there's a "[2]" maybe i made some error in my latex file somewhere.