LaTeX specific issues not fitting into one of the other forums of this category.
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hertz
- Posts: 2
- Joined: Mon May 25, 2009 10:18 pm
Post
by hertz »
Code: Select all
\documentclass[12pt,final,notitlepage,onecolumn]{article}
\usepackage{graphicx}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\setcounter{MaxMatrixCols}{30}
% by the way, you can solve this without
% installing a single piece of software...
\voffset=1.3cm
\hoffset=3.7cm
\setlength\textheight{13.37cm}
\setlength\textwidth{13.37cm}
\begin{document}
$\begin{array}[c]{ccccccccc} & & & \intercal & \vdash\dashv & \left[\begin{array}[c]{c} ^{---}\\ ---\\ \_\_\_ \end{array} \right. & & & \\ & \int & \subset\supset & \lfloor & \bigcup & \begin{array}[c]{c} --\\ \mid \end{array} & \left. \begin{array}[c]{c} \ \\ \ \end{array} \right\vert & \underset{\smile}{\overset{\frown}{\left( \ \ \ \right) }} & \diagup|\diagup\\ & & & & | & 5 & & & \\ \left\vert _{\_}\right. & \begin{array}[c]{c} \wedge\\ \longleftrightarrow\\ /\ \ \ \ \ \backslash \end{array} & \left\vert \setminus\right\vert & \vartriangleright & \int & \mid_{\_} & \begin{array}[c]{c}\cdot\\ \mid \end{array} & \overset{\_\_\_\_\ }{\left\vert_{\_\_\_\_}\right) } & \in \end{array}$
\end{document}
Could someone tell me what is the result?
NEW: TikZ book now 40% off at Amazon.com for a short time.
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frabjous
- Posts: 2064
- Joined: Fri Mar 06, 2009 12:20 am
Post
by frabjous »
The result is the following waste of time:
Ugh. 1337 comes to TeX. How sad.
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hertz
- Posts: 2
- Joined: Mon May 25, 2009 10:18 pm
Post
by hertz »
Thanks a lot.
What about this one?
Code: Select all
\documentclass{article}
\usepackage{amsmath}
\usepackage{amsfonts}
\usepackage{amssymb}
\begin{document}
$\left( y=2-\left\vert x\right\vert \wedge-2\leq x\leq2\right) \vee\left( y=1\wedge-1\leq x\leq1\right) $
$\left( y=0\wedge0\leq x\leq1\right) \vee\left( x=0\wedge0\leq y\leq2\right) $
$\left( x^{2}+y^{2}=1\wedge\left( 0\geq y\vee y\geq x\right) \right) \vee\left( y=0\wedge0\leq x\leq1\right) $
$\left( x=0\wedge-1\leq y\leq1\right) \vee\left( y^{3}=y\wedge0\leq x\leq1\right) $
$\left( x^{2}+y^{2}=2\left\vert y\right\vert \wedge x\geq0\right) \vee\left( x=0\wedge-2\leq y\leq2\right) $
$\left( x=0\wedge-2\leq y\leq2\right) \vee\left( \left( x+y=0\vee x^{2}+y^{2}=2y\right) \wedge0\leq x\leq1\right) $
$\left( y=1-\left\vert x\right\vert -\left\vert 1-\left\vert x\right\vert \right\vert \wedge-2\leq x\leq2\right) \vee\left( y=2-2\left\vert x\right\vert \wedge-1\leq x\leq1\right) $
$x=1\wedge-2\leq y\leq2$
$x^{2}+y^{2}=1\wedge x\leq\left\vert y\right\vert $
\bigskip
$\left( x=0\wedge-2\leq y\leq2\right) \vee\left( y=2\wedge-1\leq x\leq1\right) $
$y^{2}=x\left( 2-x\right) $
$\left( x=0\wedge-2\leq y\leq2\right) \vee\left( x^{2}+y^{2}=2y\wedge x\geq0\right) $
$x\left( 2+x\right) +y^{2}=0$
$\left( x=0\wedge-2\leq y\leq2\right) \vee\left( y=-2\wedge0\leq x\leq1\right) $
$x^{2}+y^{2}=1$
$\left( y=0\wedge0\leq x\cdot\left\vert x\right\vert \leq2\right) \vee\left( x^{2}+y^{2}=2\wedge\left( 0\geq y\vee y\geq x\right) \right) $
$\left( x=0\wedge-2\leq y\leq0\right) \vee\left( y=\left\vert x\right\vert \wedge-2\leq x\leq-2\right) $
\end{document}
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localghost
- Site Moderator
- Posts: 9202
- Joined: Fri Feb 02, 2007 12:06 pm
Post
by localghost »
hertz wrote:Thanks a lot.
What about this one? [...]
This is not a quiz forum. If you have serious requests, post them. But stop this senseless waste of time.
Best regards and welcome to the board
Thorsten