General ⇒ need help defining new operations with indices

[matt_at_uva]

I am trying to define a new operation that will accept an index (like \min) so that the index will appear beneath the operator in math display mode. Does anyone know how to do this?
thanks!

[Kris]

Hi,

something like this?

Code: Select all

\documentclass{article}
\newcommand{\NewOperator}[1]{\mathbf{NewOperator}_{#1}}
\begin{document}
$\NewOperator{\min} + 1 = \max$
\end{document}

Regards
Kris

[Kris]

Hi Matt,

okay, now I understand...You can achieve this
by using the amsmath-package:

Code: Select all

\documentclass{article}
\usepackage{amsmath}                  % loading amsmath-package
%...
\DeclareMathOperator{\test}{test}     % declare operator \test with sub- and superscript indices
\DeclareMathOperator*{\eff}{eff}      % declare operator \eff with above and below indices
%...
\begin{document}
\[
\test_u \neq \eff_u                   % testing new operators in math-display mode...
\]
\end{document}

You can declare new Operators with the two commands
\DeclareMathOperator and \DeclareMathOperator*.
The first one will give You sub- and superscript indices,
the one with '*' produces indices above and below the new operator...

Hope this helps!

Greetings
Kris