Graphics, Figures & Tables ⇒ Truncated equations in table

[thetasaurus]

Hello,

I'm trying to make a reference sheet of integrals, but I can't format them in a table without the symbols being truncated (as if I coded them within text).

I'm sort of new to LaTex in general, but here is the current code. Within the table are the truncated integrals, and after the table are more integrals that are formatted to look how I want them to, just not in a table.

Code: Select all

\documentclass[20pt]{amsart}
\usepackage{geometry}                % See geometry.pdf to learn the layout options. There are lots.
\geometry{letterpaper}                   % ... or a4paper or a5paper or ... 
%\geometry{landscape}                % Activate for for rotated page geometry
\usepackage[parfill]{parskip}    % Activate to begin paragraphs with an empty line rather than an indent
\usepackage{array}
\usepackage{graphicx}
\usepackage{amssymb}
\usepackage{epstopdf}
\DeclareGraphicsRule{.tif}{png}{.png}{`convert #1 `dirname #1`/`basename #1 .tif`.png}

\title{Circular Integrals}
\author{Some Name}
%\date{}                                           % Activate to display a given date or no date

\begin{document}
\maketitle
%\section{}
%\subsection{}


\begin{tabular}{l r}
$\int \sin udu= -\cos u + C \quad \quad$ & $\int \cos udu= \sin u +C$ \\
$\int \tan udu= \ln \left|\sec u \right| + C \quad \quad$ & $\int \cot udu= \ln |\sin u | + C$ \\
$\int \csc udu= \ln |\csc u - \cot u | + C \quad \quad$ & $\int \sec udu= \ln |\sec u + \tan u | + C$ \\
$\int \sec^2 udu= \tan u + C \quad \quad$ & $\int \csc^2 udu= -\cot u = C$ \\
$\int \sec u \tan udu= \sec u + C \quad \quad$ & $\int \csc u \cot udu= -\csc u + C$ \\
\end{tabular}
\\
\\
\\
$$\int \frac{1}{\sqrt{1-u^2}}du=\sin^{-1}u + C \quad \quad \int \frac{1}{u^2+1}du=\tan^{-1}u + C$$
$$\int \frac{1}{|u|\sqrt{u^2-1}}du=\sec^{-1}u + C$$
\\
$$\int \sin^{-1} udu = \sqrt{1-u^2} + u\sin^{-1} u + C \quad \quad \int \cos^{-1} udu = u \cos^{-1}u - \sqrt{1-u^2} + C$$
$$\int \tan^{-1} udu = u \tan^{-1}u - \frac{1}{2}\ln{\left(u^2+1\right)} + C  \quad \quad \int \cot^{-1} udu = u\cot^{-1}u + \frac{1}{2}\ln{\left(u^2+1\right)} + C$$
$$\int \csc^{-1} udu = -u\csc^{-1}u-\ln\left(\sqrt{u^2-1}-|u|\right) + C \quad \quad \int \sec^{-1} udu = u\sec^{-1}u + \ln\left(\sqrt{u^2-1}-|u|\right) + C$$


\end{document}  

Does anyone know how I can organize the integrals into rows and columns, but still display them at full size?

Thanks.

[localghost]

At first, some thoughts about your code.

• The font size option 20pt for the document class is invalid. See the log file for a corresponding warning. Allowed options are 10pt (default), 11pt or 12pt.
• Replace the {tabular} environment with an {array} in (in-line) math mode. Think about using the alignat* environment from amsmath instead.
• Do not use $$…$$ to introduce unnumbered displayed formulas. Use \[…\] or the starred versions of common display math environments instead.
• Do not use the amsart class if you are not bounded to certain formatting demands
• Prepare a proper minimal example next time and drop code that is not necessary to reproduce the problem.

Regarding the problem, just add \everymath={\displaystyle} to the preamble of your document.


Further reading:

• »Math mode«

Best regards and welcome to the board
Thorsten

[cgnieder]

Thorsten already gave you the very good advice (which you should follow!) to use one of amsmath's aligning environments. Just for completeness' sake here's a version with tabular (but don't do this, use amsmath's features!):

Code: Select all

\documentclass{article}
\usepackage{amsmath}
\usepackage{array}% (not only) provides \newcolumntype

% define new table columns that use displaymath for their entries
\newcolumntype{L}{>{\(\displaystyle}l<{\)}}
\newcolumntype{R}{>{\(\displaystyle}r<{\)}}

\begin{document}

\begin{tabular}{LR}
  \int \sin udu= -\cos u + C \quad \quad & \int \cos udu= \sin u +C \\
  \int \tan udu= \ln \left|\sec u \right| + C \quad \quad & \int \cot udu= \ln |\sin u | + C \\
  \int \csc udu= \ln |\csc u - \cot u | + C \quad \quad & \int \sec udu= \ln |\sec u + \tan u | + C \\
  \int \sec^2 udu= \tan u + C \quad \quad & \int \csc^2 udu= -\cot u = C \\
  \int \sec u \tan udu= \sec u + C \quad \quad & \int \csc u \cot udu= -\csc u + C \\
\end{tabular}

\end{document}

Regards