Excellent, thank you. Ended up getting it, and it didn't look too dissimilar, though I like the way you've laid it out for clarity.
Thanks - still a newbie, teaching myself as I go along... no doubt it'll get a lot easier with more practice.
Search found 4 matches
- Sun Aug 04, 2013 11:07 am
- Forum: Math & Science
- Topic: Undefined control sequence
- Replies: 4
- Views: 10945
- Sun Aug 04, 2013 10:26 am
- Forum: Math & Science
- Topic: Undefined control sequence
- Replies: 4
- Views: 10945
Undefined control sequence
Hmm, looks like \textsubscript was both a longwinded and a plain bad way of doing it!
This worked:
Gauss' law for electricity can be stated as $\nabla$$\cdot$E = {$\rho_{f}$/$\varepsilon$ where E = electric field strength (Vm\textsuperscript{-1}), $\rho_{f}$ = electric charge density (Cm ...
This worked:
Gauss' law for electricity can be stated as $\nabla$$\cdot$E = {$\rho_{f}$/$\varepsilon$ where E = electric field strength (Vm\textsuperscript{-1}), $\rho_{f}$ = electric charge density (Cm ...
- Sun Aug 04, 2013 10:17 am
- Forum: Math & Science
- Topic: Undefined control sequence
- Replies: 4
- Views: 10945
Undefined control sequence
Error message line breaks as follows:
Code: Select all
$\nabla$$\cdot$E = $\rho$\textsubscript
{f}/$\varepsilon$
- Sun Aug 04, 2013 10:15 am
- Forum: Math & Science
- Topic: Undefined control sequence
- Replies: 4
- Views: 10945
Undefined control sequence
Typing this sentence as part of my Masters literature review in physics:
Gauss' law for electricity can be stated as $\nabla$$\cdot$E = $\rho$\textsubscript{f}/$\varepsilon$ where E = electric field strength (Vm\textsuperscript{-1}), $\rho$\textsubscript{f} = electric charge density (Cm ...
Gauss' law for electricity can be stated as $\nabla$$\cdot$E = $\rho$\textsubscript{f}/$\varepsilon$ where E = electric field strength (Vm\textsuperscript{-1}), $\rho$\textsubscript{f} = electric charge density (Cm ...